Non-decreasing Function Over R Is Continuous At Any Point Except On A Countable Set Using G Delta Set (2024)

Answer:

...

Step-by-step explanation:

To find the number of calories Davis burns while running for 30 minutes, we can use the information that he burns 1080 calories running for 2.5 hours.

We know that 30 minutes is 1/120 of 2.5 hours. So, we can divide the total number of calories by 120 and we get the calorie burn for 30 minutes:

1080 calories / 120 = 9 calories

The number of calories Davis burns while swimming for 30 minutes can be determined by using the equation y = 266x, where x represents the number of hours he swims. We know that he swims for 30 minutes, or 1/120 hours, so we can plug that value into the equation:

y = 266(1/120) = 2.216 calories

So, Davis burns 7 calories more running for 30 minutes than swimming for 30 minutes, assuming the rates remain constant.

728 kilograms of sugar is used in this month.

What is Percentage?

percentage, a relative value indicating hundredth parts of any quantity.

Given that a bakery used 30% more sugar this month than last month.

Let us convert 30% to decimal.

Divide 30 by 100

30/100=0.3

the bakery used 560 kilograms of sugar last month we have to find the amount of sugar used this month.

Now multiply 30% of 560

0.3×560

168.

So now 560+168=728 is the amount of sugar used this month.

Hence, 728 kilograms of sugar is used in this month.

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Since the longest side cannot be longer than the total of the other two sides, the third side's potential lengths range from 8 to 44.

A triangle's third side must be longer than the difference between the other two sides' lengths and shorter than the total length of the other two sides. The two side lengths in this situation are 18 and 26. The third side must be greater than 8 because the difference between them is 8. The third side must be less than 44 because the total length of the first two sides equals 44. Therefore, the third side length might be any side length between 8 and 44.Since the longest side cannot be longer than the total of the other two sides, the third side's potential lengths range from 8 to 44.

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The complete question is

a triangle has one side length of 26 and another side length of 18. select all of the possible lengths of the third side potential lengths range from 8 to 44?

Answer:

Step-by-step explanation:

Part one is when you need to do area/perimiter.

DO

(a) The number of four-digit numbers with distinct digits in {1, 2, 3, 4, 5, 6} is 6543 = 360.

(b) The number of four-digit numbers in {1, 2, 3, 4, 5, 6} that are even is (3543)/2 = 270.

(c) The number of four-digit numbers in {1, 2, 3, 4, 5, 6} that are even and have distinct digits is (321*1)/2 = 3.

Four-Digit Numbers Counting

For (a) the total number of four-digit numbers with digits in {1, 2, 3, 4, 5, 6} is 6 options for the first digit, 5 for the second, 4 for the third and 3 for the last one. So, 654*3 = 360.

For (b) since digits in {1, 2, 3, 4, 5, 6} the even digits are 2,4,6. for each of the even digits we have 5 options for the second digit, 4 for the third and 3 for the last one. In total, we have 354*3= 270 even numbers.

For (c) The total number of four-digit numbers with distinct digits that are even is 211 = 2, since there are 2 even digits in {1,2,3,4,5,6} and only one of each can be used. However, this count is double-counting the numbers, so we divide by 2 to get 3.

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Answer:

5.5cm

Step-by-step explanation:

The volume of a cuboid is given by

V = lbh

where l is the length

b is the breadth

h is the height.

We know that

V = lbh = 440 cm^3

Given l = 10 cm, h = 8 cm

So, we can find b by substituting these values in the above equation

440 = 10 * b * 8

Solving for b, we get:

b = 440 / (10*8)

b = 5.5cm

So, the breadth of the cuboid is 5.5 cm.

Answer:x=4, y=5

Step-by-step explanation:

The numbers for the first eight beads that are white are; 1, 5, 9, 13, 17, 21, 25, 29

How many of the beads are white?

step1

Arithmetic Sequence

We are told that she strings in this order;

3 white1 black

Now, after the first white bead, the next white bead is the 5th bead in total.

This means the difference in interval between white beads is; 5 - 1 = 4 beads

Thus, the numbers for the first eight beads that are white are

1, (1 + 4), (1 + 4 + 4), (1 + 4 + 4 + 4)…..

Thus, we have;

1, 5, 9, 13, 17, 21, 25, 29

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The words that can be changed into mathematical or arithmetic operators are

More = +, of = *, if=Condition.

What are arithmetic operations?

Arithmetic operations is a branch of mathematics, that involves the study of numbers, operation of numbers that are useful in all the other branches of mathematics. It basically comprises operations such as Addition, Subtraction, Multiplication and Division.

These basic mathematical operations (+, -, ×, and ÷) we use in our everyday life. Whether we need to calculate the annual budget or distribute something equally to a number of people, for every such aspect of our life, we use arithmetic operations.

The four basic arithmetic operations in Maths, for all real numbers, are:

Addition (Finding the Sum; ‘+’)

Subtraction (Finding the difference; ‘-’)

Multiplication (Finding the product; ‘×’ )

Division (Finding the quotient; ‘÷’)

Now,

we can change

More = +, of = *, if=Condition as only these makes sense according to mathematics actions.

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Answer: Samantha bought 7 tickets for a concert

Step-by-step explanation:

$11.00 + $9.00 + $8.00 = 28

$196 / 28 = 7

The correct option regarding the relationship between the population of the village and time is given as follows:

A. The population is decreasing over time.

How to describe the relationship?

The variables of the scatter plot are given as follows:

Input variable: time t.Output variable: Population p.

From the points on the scatter plot, we have that when the value of t increases, the value of P decreases.

This means that the scatter plot shows a decreasing relationship, and thus the correct option is given by option A.

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The unknown values in the triangle is calculated to be

PL = 14.3 cm

CY = 7.74

NY = 9.9 mm

LJ = 8.3

How to find the unknown values in the triangle

The unknown values in the triangle is worked using SOH CAH TOA

Sin = opposite / hypotenuse - SOH

Cos = adjacent / hypotenuse - CAH

Tan = opposite / adjacent - TOA

1. using Sin = opposite / hypotenuse - SOH

sin x = PL / PX

sin 54.25 = PL / 17.62

PL = sin 54.25 * 17.62

PL = 14.3 cm

2. using Tan = opposite / adjacent - TOA

tan 52.67 = CY / 5.9

tan 52.67 * 5.9 = CY

CY = 7.74

3. using Sin = opposite / hypotenuse - SOH

sin 33.06 = YC / NY

NY = 5.4 / sin 33.06

NY = 9.9 mm

4. using Tan = opposite / adjacent - TOA

tan 55.05 = LJ / VJ

tan 55.05 * 5.8 = LJ

LJ = 8.3

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Answer:

let the price in 2016= Y

Then the price since 2016 ( since the price decreased since 2016)= (1- 27/200)Y= 0.73Y

2016 since 2016

Y 0.73Y

Y now: 4803.40

0.73Y= 4803.40

Y= 4803.40/0.73

= 6580

the cost of the panel in 2016 is 6580

Answer:

slope = 1/2

Step-by-step explanation:

rise = 3

run = 6

rise/run

3/6 = 1/2

Answer:

The slope is 1/2

Step-by-step explanation:
The slope is rise over run, from point 1 to point 2 the line rises 3.
The run from point 1 to point 2 is 6.

That means that rise over run is 3/6
Simplify this so that it is in the simplest form to get 1/2.

The image shows the rise and the run.

I hope this helps you out :D

The gallons consumed when car A travels 300 mi of city driving plus 100 mi of highway driving is 12.66 gallons

The gallons consumed when car B travels 300 mi of city driving plus 100 mi of highway driving is 13.37 gallons

The gallons consumed when car A travels 100 mi of city driving plus 300 mi of highway driving is 13.74 gallons

The gallons consumed when car B travels 100 mi of city driving plus 300 mi of highway driving is 12.54 gallons

How many gallons is consumed?

Gallons consumed when car A travels 300 mi of city driving plus 100 mi of highway driving = (300 / 33) + (100 / 28)

= 9.09 + 3.57 = 12.66 gallons

Gallons consumed when car B travels 300 mi of city driving plus 100 mi of highway driving = (300 / 29) + (100 / 33)

= 10.34 + 3.03 = 13.37 gallons

Gallons consumed when car A travels 100 mi of city driving plus 300 mi of highway driving = (100 / 33) + (300 / 28)

= 3.03 + 10.71 =13.74 gallons

Gallons consumed when car B travels 100 mi of city driving plus 300 mi of highway driving = (100 / 29) + (300 /33)

= 3.45 + 9.09 = 12.54 gallons

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Qualitative data is data that cannot be counted easily using numbers is not have the correct definitions.

Qualitative data is used to address the research questionnaire regarding whats and how many(s) or also for research procedures to quantify a problem. This data can be used to compare or count data on a numerical scale.

This type of research typically involves in-depth interviews, focus groups, or observations in order to collect data that is rich in detail and context. This data is used for Qualitative research which is very helpful when understanding social reality and the attributes, beliefs, and motivations of people.

The main importance of this kind of project come into the limelight when someone is trying to understand the reason behind one's beliefs or behaviors.

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The required length of a side of the rhombus is 10 cm.

What is Rhombus?

A parallelogram is a particular instance of a rhombus. The opposing sides and angles in a rhombus are parallel and equal. A rhombus also has equal-length sides on each side, and its diagonals meet at right angles to form its shape. The rhombus is also referred to as a diamond or rhombus.

According to question:

Let diagonals intersect each other at o,

In ΔROQ

RQ = [tex]\sqrt{OR^{2}+OQ^{2}}[/tex]

RQ =[tex]\sqrt{36+64} =\sqrt{100}[/tex]

RQ = 10 cm

Thus, required length of the side of rhombus is 10 cm.

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Complete question:

PQRS is a rhombus. The shorter diagonal PR measures 12 units and QS = 16 units. The measure of angle PQR = 60°. Find the length of a side of the rhombus.​

Answer:

Step-by-step explanation:

Each mechanic worked a total of 12.5 hours each.

The total length of A+C will be 172 cm(unit).

What is a unit?

Units are the tools to measure and compare different things. Comparison becomes easy when all the units for the measurement are the same. Different units can be classified depending on their use. A few of the units can be classified as:

The seven SI base units (The International System of Units (SI), commonly known as the metric system, is the international standard for measurement) which are comprised of:

Length - meter (m)

Time - second (s)

Amount of substance - mole (mole)

Electric current - ampere (A)

Temperature - kelvin (K)

Luminous intensity - candela (cd)

Mass - kilogram (kg)

Now,

Given B-A=120 -->1

B-C=84 -->2

A+B+C=360 -->3

Therefore, from equations 1,2 and 3

B-120+B+B-84=360

B=188

By putting B=188 in 1 and 2

A=68

C=104

A+C=172cm

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Answer:

x-3 =0 or x-8 =0

x= +3 or x = +8

Total 18 different paths are there from a to b that go through the point circled in the following lattice

In the given question, we have to find how many different paths are there from a to b that go through the point circled in the following lattice.

The diagram of the lattice is given below:

Therefore, we must first go from A to the encircled point.

We must travel 2 horizontally and 2 vertically to do that.

Now, to get to this point, we have ways = [tex]C_{2}^{4}[/tex] ways

Total ways to go from A to the encircled point = [tex]\frac{4!}{2!(4-2)!}[/tex]

Total ways to go from A to the encircled point = 6 ways

Additionally, we must travel 2 horizontal and 1 vertical units to get from the encircling point to B.

As a result, total ways to go from the encircling point to B = [tex]C^{3}_{1}[/tex]

Total ways to go from the encircling point to B = [tex]\frac{3!}{1!(3-1)!}[/tex]

Total ways to go from the encircling point to B = 3 ways

So, different paths are there from a to b = 6×3

Different paths are there from a to b = 18 ways

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The coordinates of point p along the directed line segment ab are [tex]$p(-1,-2)$[/tex]

Let the coordinates of point p be (x,y)

The ratio of ap to pb is 2 to 6, so we have [tex]$$\frac{|ap|}{|pb|} = \frac{2}{6}$$[/tex]

We can calculate the distances between points $a$ and $p$ and points $p$ and $b$ using the distance formula as follows:

[tex]$$|ap| = \sqrt{(x+3)^2+(y-2)^2}$$$$|pb| = \sqrt{(5-x)^2+(y+4)^2}$$[/tex]

We can use the ratio of the distances to set up a proportion to solve for $x$ and $y$:

[tex]$$\frac{|ap|}{|pb|} = \frac{2}{6} \implies \frac{\sqrt{(x+3)^2+(y-2)^2}}{\sqrt{(5-x)^2+(y+4)^2}} = \frac{2}{6}$$\\[/tex]

Solving for $x$ and $y$, we get $x = -1$ and $y = -2$.

Therefore, the coordinates of point $p$ along the directed line segment $ab$ are [tex]$p(-1,-2)$[/tex]

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Answer:

The equation Jared can use to find the rate at which he drove is:

rate (r) = distance (d) / time (t)

So in this case, Jared can plug in the values he knows into the equation:

r = 15 miles / 0.5 hours

Solving for r, he can find the rate at which he drove:

r = 30 miles per hour.

So Jared drove at a rate of 30 miles per hour.

Step-by-step explanation:

PLEASE GIVE BRAINLIEST

A counterexample to the statement given in this problem is:

Three colinear points.

How to obtain the counter example on this problem?

The statement for this problem is given as follows:

You can connect any three points to form a triangle.

This statement is false, as for example, three points on a line do not form a function.

The counterexample is the statement that proves that a conjecture(another statement) is false, hence the first option is the correct option in the context of this problem.

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The value of x is 900 and value of y is 300.

What is Equation?

Two or more expressions with an Equal sign is called as Equation.

From the given information we form a system of linear equations.

1.4x+1.6y=1740..(1)

x-3y=0..(2)

x=3y

Plug in x =3y in the equation 1.

1.4(3y)+1.6y=1740

4.2y+1.6y=1740

5.8y=1740

Divide both sides by 5.8

y=300

x=3(300)=900

Hence, the value of x is 900 and value of y is 300.

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The sampling distribution of a statistic is the distribution of values taken by the statistic in all possible samples of the same size from the same population.

The population parameter is the true value of the statistic for the entire population. The probability that the statistic is obtained is the probability that it will be obtained in a single sample from the population. The variance of the values is the amount of variation among the values of the statistic in the sample. The formula for calculating the variance is the sum of the squared deviations from the mean, divided by the number of values in the sample. This can be written mathematically as: Variance = Σ (x - X)2/ n, where x is each value in the sample, X is the mean value, and n is the number of values in the sample.

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(a) (i) Average velocity = -160 ft/s, (ii) Average velocity = -320 ft/s, (iii) Average velocity = -1600 ft/s. (b) Instantaneous velocity = -320 ft/s.

(a) (i) Average velocity = change in height/change in time

= (285 - (285 - 16(2.1)^2))/0.1

= -160 ft/s

(ii) Average velocity

= (285 - (285 - 16(2.05)^2))/0.05

= -320 ft/s

(iii) Average velocity

= (285 - (285 - 16(2.01)^2))/0.01

= -1600 ft/s.

(b) Instantaneous velocity = -320 ft/s.

The average velocity of the pebble after t seconds is given by the equation y = 285 − 16t2. To find the average velocity for the time period beginning when t = 2, we can calculate the change in height of the pebble over the given time period and divide it by the change in time. For instance, for 0.1 seconds, we can calculate the average velocity by dividing the change in height (285 - (285 - 16(2.1)^2)) by the change in time (0.1). This gives us an average velocity of -160 ft/s. Similarly, for 0.05 and 0.01 seconds, the average velocity can be calculated to be -320 ft/s and -1600 ft/s respectively. To estimate the instantaneous velocity of the pebble after 2 seconds, we can assume that the change in time is very small and approximate the velocity to be the average velocity for 0.01 seconds. This gives us an instantaneous velocity of -320 ft/s.

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The value of the variable x = π³ - π/π

What are algebraic expressions?

Algebraic expressions are described as mathematical expressions that are comprised of variables, factors, constants, terms and coefficients.

These algebraic expressions are also comprised of arithmetic operations, such as;

DivisionMultiplicationSubtractionFloor divisionAdditionBracketParentheses

From the information, we have that;

y = π³

y = πx + π

Substitute the values, we get;

π³ = πx + π

collect like terms

π³ - π = πx

Divide both sides by the coefficient of x

x = π³ - π/π

Thus, the value is x = π³ - π/π

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Haley is right because the solution is r ≤ -20

What is an equation?

An equation is an expression that shows the relationship between numbers and variables.

Inequalities is used for the non equal comparison of these numbers and variables.

Given the inequality:

-13 ≥ r + 7

Add 13 to both sides:

-13 + 13 ≥ r + 7 + 13

0 ≥ r + 20

subtract r from both sides:

0 - r ≥ r + 20 - r

-r ≥ 20

divide both sides by -1:

r ≤ -20

The solution is a graph on a number line with a solid circle at -20 and an arrow pointing left

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A polynomial equation of the second degree, or a quadratic, must contain at least one squared term to be considered a quadratic.

Which quadratic equation is the most fundamental?

Quadratic equations or quadratic functions. A polynomial equation of the second degree, or a quadratic, must contain at least one squared term to be considered a quadratic. Equations using quadratics is another name for it. The quadratic equation is expressed in its general form as ax2 + bx + c = 0.

For instance, 6x2 + 11x - 35 = 0, 2x2 - 4x - 2 = 0, 2x2 - 64 = 0, x2 - 16 = 0, x2 - 7x = 0, 2x2 + 8x = 0, etc. are examples of quadratic equations.

Three kinds of quadratics are frequently employed:

Standard Form: y = an x 2 + b x + c y = an x 2 + b x + c

y = a (x r 1, x r 2) is the factored form. y=a(x-r 1)(x-r 2) y=a(x−r1)(x−r2)

Vertex Formula: y=a (x h) 2 + k y=a (x-h)2 + k y=a (x-h) 2+k.

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